给定一个矩阵，我们需要打印矩阵的边界元素并显示它们的总和。
示例参考下面给出的矩阵 -
给定矩阵1 2 34 5 67 8 9
边界矩阵1 2 34 67 8 9
边界元素之和：1 + 2 + 3 + 4 + 6 + 7 + 8 + 9 = 40
求边界矩阵之和的逻辑如下如下 -
for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("
");}
程序以下是用于打印矩阵边界元素之和的c程序 -
#include<stdio.h>#include<limits.h>int main(){ int m, n, sum = 0; printf("
enter the order of the matrix : "); scanf("%d %d",&m,&n); int i, j; int mat[m][n]; printf("
input the matrix elements
"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++) scanf("%d",&mat[i][j]); } printf("
boundary matrix
"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("
"); } printf("
sum of boundary is %d", sum);}
输出当执行上述程序时，会产生以下结果 -
enter the order of the matrix : 3 3input the matrix elements :1 2 34 5 67 8 9boundary matrix :1 2 34 67 8 9sum of boundary is 40
以上就是打印矩阵边界元素之和的c程序的详细内容。