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mysql用户自定义函数实例与部分问题解决方法_MySQL

mysql用户自定义函数实例与部分问题解决方法_mysql
一、查看创建函数的功能是否开启:
mysql> show variables like '%func%'; +-----------------------------------------+-------+ | variable_name | value | +-----------------------------------------+-------+ | log_bin_trust_function_creators | on | +-----------------------------------------+-------+ 1 row in set (0.02 sec)
二、如果value处值为off,则需将其开启。
mysql> set global log_bin_trust_function_creators=1; use app02 delimiter // mysql>drop function if exists `testhanshu`; create function `testhanshu`(`tustate` int) returns varchar(2000) begin declare oneaddr varchar(200) default ''; declare alladdr varchar(2000) default ''; declare done int default false; declare curl cursor for select utruename from tsys_user where ustate = tustate; declare continue handler for not found set done = 1; open curl; repeat fetch curl into oneaddr; if not done then set oneaddr = concat(oneaddr, ';'); set alladdr = concat(alladdr, oneaddr); end if; until done end repeat; close curl; return alladdr; end; mysql>select testhanshu(1);
在使用mysql自己定义的函数时,出现错误java.sql.sqlexception: this function has none of deterministic, no sql, or reads sql data in its declaration and binary logging is enabled (you *might* want to use the less safe log_bin_trust_function_creators variable)
解决办法有三种:
1. 登录mysql客户端,执行: set global log_bin_trust_function_creators = 1;
2.在登录mysql服务器是,在服务启动时加上 “--log-bin-trust-function-creators=1 ”参数并设置为1。
3.在my.ini(my.cnf)中的[mysqld]区段中加上 log-bin-trust-function-creators=1。
以上就是mysql用户自定义函数实例与部分问题解决方法_mysql的内容。
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