求一个效果的对比显示
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2120844 dj小罗remix这该死的温柔disco
2120843 lucky_twice-魔法项链第一首-dj-舞曲-慢摇
2120842 beautiful_girls_(dj→梦←extended_remix)
2120841 djruico_funkyhouse_remix
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okndr1 djruico_funkyhouse_remix
dgerr2 lucky_twice-魔法项链第一首-dj-舞曲-慢摇
egdsf3 dj小罗remix这该死的温柔disco
eeeed4 beautiful_girls_(dj→梦←extended_remix)
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要实现的效果为:
dj小罗remix这该死的温柔disco [a]2120844[/a] [bb]egdsf3[/bb]  
lucky_twice-魔法项链第一首-dj-舞曲-慢摇 [a]2120843[/a][bb]dgerr2[/bb]
beautiful_girls_(dj→梦←extended_remix) [a]2120842[/a][bb]eeeed4[/bb]
djruico_funkyhouse_remix [a]2120841[/a][bb]okndr1[/bb]
其实就是把，a和b记录对比，拿名称做一个唯一的对比，
我想到思路可不知道用什么代码做好。js 还是asp 还是php
------解决方案--------------------
php code$a = array( array('2120844', 'dj小罗remix这该死的温柔disco'), array('2120843', 'lucky_twice-魔法项链第一首-dj-舞曲-慢摇'), array('2120842', 'beautiful_girls_(dj→梦←extended_remix)'), array('2120841', 'djruico_funkyhouse_remix'),);$b = array( array('okndr1', 'djruico_funkyhouse_remix'), array('dgerr2', 'lucky_twice-魔法项链第一首-dj-舞曲-慢摇'), array('egdsf3', 'dj小罗remix这该死的温柔disco'), array('eeeed4', 'beautiful_girls_(dj→梦←extended_remix)'),);$r = array();foreach($a as $v) $r[$v[1]][] = $v[0];foreach($b as $v) $r[$v[1]][] = $v[0];foreach($r as $k=>$v) echo $k [a]$v[0][/a] [bb]$v[1][/bb]\n;
------解决方案--------------------

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