请问如何在内容模板中写标题和内容呢
这是php文件,请问如何在内容模板中写标题和内容呢?请大神给写一个单条内容的模板。谢谢了,,由于代码太长,我删了一部份,急用,谢谢各位好心人了
spargs('uid')){
$uid = (int) $this->spargs('uid');
$cond = and b.uid = '$uid';
}
if($this->spargs('pagelimit')){
$pagelimit = ($this->spargs('pagelimit') spargs('pagelimit') : 30 ; //自定义分页
}else{
$pagelimit = $this->yb['show_page_num'];
}
//left join `.dbpre.follow` as f on ( b.uid = f.touid and f.uid = '$uid' )
$sql = select b. * , k.id as likeid ,m.username,m.domain
from `.dbpre.blog` as b left join `.dbpre.likes` as k on ( b.bid = k.bid and k.uid ='$this->uid' )
left join `.dbpre.member` as m on b.uid = m.uid where b.open = 1 $cond order by b.time desc;
$data['blog'] = spclass('db_blog')->sppager($this->spargs('page',1),$pagelimit)->findsql($sql);
$data['page'] = spclass('db_blog')->sppager()->getpager();
unset($data['page']['all_pages']);
if(!empty($data['blog'])){
foreach($data['blog'] as &$d){
$this->foramt_feeds($d);
}
$this->api_success($data);
}else{
$this->api_success();
}
}
//获取单个博客
function getoneblog(){
$bid = (int) $this->spargs('bid');
$sql = select b. * , k.id as likeid ,m.username,m.domain
from `.dbpre.blog` as b left join `.dbpre.likes` as k on ( b.bid = k.bid and k.uid ='$this->uid' )
left join `.dbpre.member` as m on b.uid = m.uid where b.open in (1,-2) and b.bid = '$bid';
$data['blog'] = spclass('db_blog')->findsql($sql);
foreach($data['blog'] as &$d){
$this->foramt_feeds($d,0);
}
$this->api_success($data);
}
//获取我关注的用户feeds
function followfeeds(){
$followuid = spclass('db_follow')->getfollowuid($this->uid);
if($followuid){
$sql = select b. * , k.id as likeid ,m.username,m.domain
from `.dbpre.blog` as b left join `.dbpre.likes` as k on ( b.bid = k.bid and k.uid ='$this->uid' )
left join `.dbpre.member` as m on b.uid = m.uid where b.open = 1;
$sql .= and b.uid in ($followuid) and b.open=1 order by b.time desc;
$data['blog'] = spclass('db_blog')->sppager($this->spargs('page',1),10)->findsql($sql);
$data['page'] = spclass('db_blog')->sppager()->getpager();
foreach($data['blog'] as &$d){
$this->foramt_feeds($d);
}
}
$this->api_success($data);