这段代码中echo怎么不执行呢，高手给支个招
本帖最后由 xuzuning 于 2014-07-01 17:05:54 编辑 public function add(){
$this->lottory_record_db=m('lottery_record');
$this->lottory_db=m('lottery');
if($_post['action'] == 'add' ){
$lid = $this->_post('lid');
$wechaid = $this->_post('wechaid');
//$data['sn'] = $this->_post('sncode');
$data['phone'] = $this->_post('tel');
//$data['prize'] = $this->_post('winprize');
$data['wecha_name'] = $this->_post('wxname');
//$data['time'] = time();
//$data['islottery'] = 1;
//$data['usenums'] = 1;
$rid=intval($this->_post('rid'));
if (!$rid){
$thisrecord=$this->lottory_record_db->where(array('lid'=>$lid,'wecha_id'=>$wechaid,'islottery'=>1))->find();
$rid=$thisrecord['id'];
}
$rollback = $this->lottory_record_db->where(array('lid'=>$lid,'wecha_id'=>$wechaid,'id'=>$rid))->save($data);
$record=$this->lottory_record_db->where(array('id'=>$rid))->find();
echo'{success:1,msg:恭喜！尊敬的'.$data['wecha_name'].'请您保持手机通畅！你的领奖序号:'.$record['sn'].'}';
exit;
}
}
------解决方案--------------------
if($_post['action'] == 'add' ){
条件 $_post['action'] == 'add' 不成立，所以 echo 不执行
------解决方案--------------------
var_dump($_post['action']);//输出看看值是什么？确定条件成立？

------解决方案--------------------
var_dump($_post['action']);
------解决方案--------------------
那你输出的只是一个 json 串，需要 js 代码去解析呀