例如有这样一条语句select uid from user where uid = 70 or uid =68 or uid = 69;
mysql返回的是
68
69
70
如何让mysql返回
70
68
69
这样的结果,就是按照where的条件先后来返回.
回复内容： 例如有这样一条语句select uid from user where uid = 70 or uid =68 or uid = 69;
mysql返回的是
68
69
70
如何让mysql返回
70
68
69
这样的结果,就是按照where的条件先后来返回.
select id, namefrom mytablewhere name in ('b', 'a', 'd', 'e', 'c')order by field(name, 'b', 'a', 'd', 'e', 'c')
网上随便找下就有了
select uid from user where uid in( 70 ,68 , 69) order by fine_in_set('uid','70,68,69');
select uid from user where uid = 70 or uid =68 or uid = 69 order by uid desc
select uid from user where uid = 70 or uid =68 or uid = 69 order by uid desc;