php比较相似字符串的方法 本文实例讲述了php比较相似字符串的方法。分享给大家供大家参考。具体分析如下：
这里通过php的similar_text函数比较两个字符串的相似性。
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$word2compare = stupid;
$words = array(
'stupid',
'stu and pid',
'hello',
'foobar',
'stpid',
'upid',
'stuuupid',
'sstuuupiiid',
);
while(list($id, $str) = each($words)){
similar_text($str, $word2compare, $percent);
print comparing '$word2compare' with '$str': ;
print round($percent) . %\n;
}
/*
results:
comparing 'stupid' with 'stupid': 100%
comparing 'stupid' with 'stu and pid': 71%
comparing 'stupid' with 'hello': 0%
comparing 'stupid' with 'foobar': 0%
comparing 'stupid' with 'stpid': 91%
comparing 'stupid' with 'upid': 80%
comparing 'stupid' with 'stuuupid': 86%
comparing 'stupid' with 'sstuuupiiid': 71%
*/
希望本文所述对大家的php程序设计有所帮助。
http://www.bkjia.com/phpjc/1012363.htmlwww.bkjia.comtruehttp://www.bkjia.com/phpjc/1012363.htmltecharticlephp比较相似字符串的方法 本文实例讲述了php比较相似字符串的方法。分享给大家供大家参考。具体分析如下： 这里通过php的similar_text函数...