数组是一组以单一名称存储的相关数据项。
例如 int student[30]; //student是一个数组名，包含单个变量名的30个数据项集合
数组的操作搜索 - 用于查找特定元素是否存在
排序 - 它有助于排列数组中的元素按升序或降序排列。
遍历 - 它按顺序处理数组中的每个元素。
插入 - 它有助于在数组中插入元素。
删除 - 它有助于删除数组中的元素。数组中的元素。
在数组中查找偶数的逻辑如下 -
for(i = 0; i < size; i ++){ if(a[i] % 2 == 0){ even[ecount] = a[i]; ecount++; }}
在数组中查找奇数的逻辑如下 -
for(i = 0; i < size; i ++){ if(a[i] % 2 != 0){ odd[ocount] = a[i]; ocount++; }}
要显示偶数，请调用下面提到的显示函数 -
printf("no: of elements comes under even are = %d
", ecount);printf("the elements that are present in an even array is: ");void display(int a[], int size){ int i; for(i = 0; i < size; i++){ printf("%d \t ", a[i]); } printf("
");}
要显示奇数，请按照以下方式调用显示函数 −
printf("no: of elements comes under odd are = %d
", ocount);printf("the elements that are present in an odd array is : ");void display(int a[], int size){ int i; for(i = 0; i < size; i++){ printf("%d \t ", a[i]); } printf("
");}
程序以下是使用 for 循环分隔数组中偶数和奇数的 c 程序 -
 现场演示
#include<stdio.h>void display(int a[], int size);int main(){ int size, i, a[10], even[20], odd[20]; int ecount = 0, ocount = 0; printf("enter size of array :
"); scanf("%d", &size); printf("enter array elements:
"); for(i = 0; i < size; i++){ scanf("%d", &a[i]); } for(i = 0; i < size; i ++){ if(a[i] % 2 == 0){ even[ecount] = a[i]; ecount++; } else{ odd[ocount] = a[i]; ocount++; } } printf("no: of elements comes under even are = %d
", ecount); printf("the elements that are present in an even array is: "); display(even, ecount); printf("no: of elements comes under odd are = %d
", ocount); printf("the elements that are present in an odd array is : "); display(odd, ocount); return 0;}void display(int a[], int size){ int i; for(i = 0; i < size; i++){ printf("%d \t ", a[i]); } printf("
");}
输出当执行上述程序时，会产生以下结果 -
enter size of array:5enter array elements:2345671234no: of elements comes under even are = 2the elements that are present in an even array is: 12 34no: of elements comes under odd are = 3the elements that are present in an odd array is : 23 45 67
以上就是如何使用c语言中的for循环将数组中的偶数和奇数分开？的详细内容。