$connect = mysqli_connect(host,user,password,db) or die(error . mysqli_error($connect));$result = mysql_query('select * from admin',$connnet);print(mysql_num_rows($result));mysql_close();

报错：
warning: mysql_query(): supplied argument is not a valid mysql-link resourcewarning: mysql_num_rows(): supplied argument is not a valid mysql result resourcewarning: mysql_close(): no mysql-link resource supplied

而使用面向对象方法则没有问题
请问这是什么问题？
回复内容： $connect = mysqli_connect(host,user,password,db) or die(error . mysqli_error($connect));$result = mysql_query('select * from admin',$connnet);print(mysql_num_rows($result));mysql_close();

报错：
warning: mysql_query(): supplied argument is not a valid mysql-link resourcewarning: mysql_num_rows(): supplied argument is not a valid mysql result resourcewarning: mysql_close(): no mysql-link resource supplied

而使用面向对象方法则没有问题
请问这是什么问题？
因为你写错字母了...
第一个变量是 $connect
第二个变量是 $connnect
多了一个n，好不？
当然，也要用mysqli_query而不是mysql_query
mysql_query -> mysqli_query
mysql_num_rows -> mysqli_num_rows
mysql_close -> mysqli_close
哥们你用mysqli_connect创建的连接得用mysqli_xxx来用
mysqli_xxx和mysql_xxx是不能混用的