我希望点击“updqte”按钮后按钮变成“save”，然后单元格变成文本框，编辑完文本框后点击“save”结果提交给了数据库。按钮改变用js做完了，其他的实在是不回了，各位大神帮帮忙吧。
<!doctype html public "-//w3c//dtd html 4.01 transitional//en"
"http://www.w3.org/tr/html4/loose.dtd"><html><head><meta http-equiv="content-type"
content="text/html;
charset=utf-8"><title>insert title here</title><script language="javascript" type="text/javascript">
function showtd(num) {
document.getelementbyid("bg"+num).style.display = "none";
document.getelementbyid("show"+num).style.display = "block";
}
function hidetd(num) {
document.getelementbyid("bg"+num).style.display = 'block';
document.getelementbyid("show"+num).style.display = 'none';
}
function change()
{
var tds = document.getelementsbytagname("td");
var t1 = document.getelementbyid("a").innerhtml;
var txt = document.createelement("input");
txt.type = "text";
txt.value = t1;
txt.id = "sort_t";
tds[29].appendchild(txt);
txt.select();
}
function mouseup(){
if (document.getelementbyid("sort_t") && event.srcelement.id != "sort_t")
{
var obj = document.getelementbyid("sort_t").parentelement;
var txtvalue = document.getelementbyid("sort_t").value;
obj.innertext = txtvalue;
}
}
</script></head><body><form><table border="1">
<?php
$db = mysql_connect('localhost','root','root');
mysql_select_db('ec',$db);
if (!$db)
{
die('could not connect: ' . mysql_error());
}
$result = mysql_query("select * from goods");
echo "<tr><th>goodsid</th><th>barcode</th>
<th>goodsname</th>
<th>category</th>
<th>specifications</th>
<th>manufacturers</th>
<th>numbers</th>
<th>instructions</th>
<th>pictures</th>
<th>update</th>
<th>delete</th></tr>";
$n = 0;while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>"; echo "<td>" . $row['barcode'] . "</td>";
echo "<td>" . $row['goods_name'] . "</td>";
echo "<td>" . $row['category'] . "</td>";
echo "<td>" . $row['specifications'] . "</td>";
echo "<td>" . $row['manufacturers'] . "</td>";
echo "<td>" . $row['number'] . "</td>";
echo "<td>" . $row['instruction'] . "</td>";
echo "<td>" . "<img src = '$row[picture_url]' style='width:80px;height=60px'/>" . "</td>";
echo "<td id='bg$n'>".
"<input id='btnshow$n' type='button' value='update' onclick='showtd($n)'/>".
"</td>".
"<td id='show$n' style='display:none'>".
"<input id='btnclose$n' type='button' value='save' onclick='hidetd($n)'/>".
"</td>"; echo "<td>"."<a href='delete.php?id=$row[id]'>"."delete"."</a>"."</td>";
echo "</tr>";
++$n;
}
mysql_close($db);
?>
</table></form>
</body></html>
回复讨论(解决方案)
1.给你的save按钮一个onclick方法 点击后触发
2.用ajax 提交参数到后台，调用php程序
3.然后将接收内容提交到数据库
4.成功or失败返回到页面
你这里要用到ajax来提交数据
1.给你的save按钮一个onclick方法 点击后触发
2.用ajax 提交参数到后台，调用php程序
3.然后将接收内容提交到数据库
4.成功or失败返回到页面
<!doctype html public "-//w3c//dtd html 4.01 transitional//en"
"http://www.w3.org/tr/html4/loose.dtd"><html><head><meta http-equiv="content-type"
content="text/html; charset=utf-8"><title>insert title here</title><script language="javascript" type="text/javascript">
function showtd(num) {
document.getelementbyid("bg"+num).style.display = "none";
document.getelementbyid("show"+num).style.display = "block";
}
function hidetd(num) {
document.getelementbyid("bg"+num).style.display = 'block';
document.getelementbyid("show"+num).style.display = 'none';
}
function change()
{
var tds = document.getelementsbytagname("td");
var t1 = document.getelementbyid("a").innerhtml;
var txt = document.createelement("input");
txt.type = "text";
txt.value = t1;
txt.id = "sort_t";
tds[30].appendchild(txt);
txt.select();
}
function mouseup(){
if (document.getelementbyid("sort_t") && event.srcelement.id != "sort_t")
{
var obj = document.getelementbyid("sort_t").parentelement;
var txtvalue = document.getelementbyid("sort_t").value;
obj.innertext = txtvalue;
}
}
</script></head><body>
<form>
<table border="1">
<?php
$db = mysql_connect('localhost','root','root');
mysql_select_db('ec',$db);
if (!$db)
{
die('could not connect: ' . mysql_error());
}
$result = mysql_query("select * from goods");
echo "<tr>
<th>goodsid</th>
<th>barcode</th>
<th>goodsname</th>
<th>category</th>
<th>specifications</th>
<th>manufacturers</th>
<th>numbers</th>
<th>instructions</th>
<th>pictures</th>
<th>update</th>
<th>delete</th>
</tr>";
$n = 0;
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td id='a'>" . $row['barcode'] . "</td>";
echo "<td>" . $row['goods_name'] . "</td>";
echo "<td>" . $row['category'] . "</td>";
echo "<td>" . $row['specifications'] . "</td>";
echo "<td>" . $row['manufacturers'] . "</td>"; echo "<td>" . $row['number'] . "</td>";
echo "<td>" . $row['instruction'] . "</td>";
echo "<td>" . "<img src = '$row[picture_url]' style='width:80px;height=60px'/>" . "</td>";
echo "<td id='bg$n'>".
"<input id='btnshow$n' type='button' value='update' onclick='showtd($n);change()' />".
"</td>".
"<td id='show$n' style='display:none'>".
"<input id='btnclose$n' type='button' value='save' onclick='hidetd($n);mouseup()'/>".
"</td>";
echo "<td>"."<a href='delete.php?id=$row[id]'>"."delete"."</a>"."</td>";
echo "</tr>";
++$n;
}
mysql_close($db);
?>
</table></form>
</body></html>
我表上红色的部分是一个数组，我想让这个数组变成动态的，要不然所有按钮都只操作一条数据。有什么好办法没？
1.给你的save按钮一个onclick方法 点击后触发
2.用ajax 提交参数到后台，调用php程序
3.然后将接收内容提交到数据库
4.成功or失败返回到页面
不好意思是第24行，刚才没标上颜色。
要是我做的话就是都设为隐藏的
一个.show()
一个.hide()
当点击完一个操作就触发函数转换到另一个按钮
建议lz选择jq选择器都很强大
搭配ajax 足够完成大量input提交工作
你这里要用到ajax来提交数据
<!doctype html public "-//w3c//dtd html 4.01 transitional//en"
"http://www.w3.org/tr/html4/loose.dtd"><html><head><meta http-equiv="content-type"
content="text/html; charset=utf-8"><title>insert title here</title><script language="javascript" type="text/javascript">
function showtd(num) {
document.getelementbyid("bg"+num).style.display = "none";
document.getelementbyid("show"+num).style.display = "block";
}
function hidetd(num) {
document.getelementbyid("bg"+num).style.display = 'block';
document.getelementbyid("show"+num).style.display = 'none';
}
function change()
{
var tds = document.getelementsbytagname("td");
var t1 = document.getelementbyid("a").innerhtml;
var txt = document.createelement("input");
txt.type = "text";
txt.value = t1;
txt.id = "sort_t";
tds[29].appendchild(txt);
txt.select();
}
function mouseup(){
if (document.getelementbyid("sort_t") && event.srcelement.id != "sort_t")
{
var obj = document.getelementbyid("sort_t").parentelement;
var txtvalue = document.getelementbyid("sort_t").value;
obj.innertext = txtvalue;
}
}
</script></head><body><form><table border="1">
<?php
$db = mysql_connect('localhost','root','root');
mysql_select_db('ec',$db);
if (!$db)
{
die('could not connect: ' . mysql_error());
}
$result = mysql_query("select * from goods");
echo "<tr><th>goodsid</th>
<th>barcode</th><th>goodsname</th><th>category</th><th>specifications</th><th>manufacturers</th>
<th>numbers</th><th>instructions</th><th>pictures</th><th>update</th><th>delete</th></tr>";
$n = 0;
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td id='a'>" . $row['barcode'] . "</td>";
echo "<td>" . $row['goods_name'] . "</td>";
echo "<td>" . $row['category'] . "</td>";
echo "<td>" . $row['specifications'] . "</td>";
echo "<td>" . $row['manufacturers'] . "</td>";
echo "<td>" . $row['number'] . "</td>";
echo "<td>" . $row['instruction'] . "</td>";
echo "<td>" . "<img src = '$row[picture_url]' style='width:80px;height=60px'/>" . "</td>";
echo "<td id='bg$n'>".
"<input id='btnshow$n' type='button' value='update' onclick='showtd($n);change()' />".
"</td>".
"<td id='show$n' style='display:none'>".
"<input id='btnclose$n' type='button' value='save' onclick='hidetd($n);mouseup()'/>".
"</td>";
echo "<td>"."<a href='delete.php?id=$row[id]'>"."delete"."</a>"."</td>";
echo "</tr>";
++$n;
}
mysql_close($db);
?>
</table></form></body></html>
第24行的那个数组能不能改成动态的，要不然所有按钮都只操作同一条数据，应该怎么改啊？
<html><head><script type="text/javascript" src="/jquery/jquery.js">
</script><script type="text/javascript">
$(document).ready(function(){ $(".btn1").click(function(){
$(".btn1").hide(); $(".btn2").show(); });
$(".btn2").click(function(){
$(".btn1").show();
$(".btn2").hide();
});
});
</script></head><body><button class="btn1" style="display:none">update</button><button class="btn2">save</button></body></html>
刚才描述的不是很清楚 写了个测试的代码 你可以参考
xml/html code
?
12345678910111213141516171819202122
<html> <head> <script type="text/javascript" src="/jquery/jquery.js"></script> <script type="text/javascript"> $(document).ready(function……
谢谢你，我没学过ajax和jq。
items = tds.join(',');
好固执的孩纸啊
function change(obj)
{
//可以传递个当前对象过来
var tds = document.getelementsbytagname("td");
var t1 = document.getelementbyid("a").innerhtml;
var txt = document.createelement("input");
txt.type = "text";
txt.value = t1;
txt.id = "sort_t";
obj.parentnode.childnodes[1].appendchild(txt);
//添加至第二个td，可根据需要修改
txt.select();
}
调用时，
change(this)
还有你的id命名重复了，这样只能获取第一个