本文实例讲述了python检查字符串是否是正确isbn的方法。分享给大家供大家参考。具体实现方法如下：
def isisbn(isbn): checks if the passed string is a valid isbn number. if len(isbn) != 10 or not isbn[:9].isdigit(): return false if not (isbn[9].isdigit() or isbn[9].lower() == x): return false tot = sum((10 - i) * int(c) for i, c in enumerate(isbn[:-1])) checksum = (11 - tot % 11) % 11 if isbn[9] == 'x' or isbn[9] == 'x': return checksum == 10 else: return checksum == int(isbn[9]) ok = 031234161x 0525949488 076360013x 0671027360 0803612079 0307263118 0684856093 0767916565 0071392319 1400032806 0765305240 for code in ok.split(): assert isisbn(code) bad = 0312341613 052594948x 0763600138 0671027364 080361207x 0307263110 0684856092 0767916567 0071392318 1400032801 0765305241 031234161 076530y241 068485609y for code in bad.split(): assert not isisbn(code) print tests of isisbn()passed.
希望本文所述对大家的python程序设计有所帮助。