public function pai3(&$actionno, &$actiontime, $time=null){ $this->settimeno($actiontime, $time); //echo $actiontime,' ',date('y-m-d h:i:s', $time); if($actiontime >= date('y-m-d h:i:s', $time)){ $actionno = date('yz', $time)-6; }else{ $actionno = date('yz', $time)-6; $actiontime=date('y-m-d 18:30', $time); } }
上面代码读取的年和号，如201456我想改成2014056增加一位，请问怎么改？
回复讨论(解决方案) $year = date('y', time());$day = str_pad(date('z',time()),3,'0',str_pad_left);echo $year.$day;

$year = date('y', time());$day = str_pad(date('z',time()),3,'0',str_pad_left);echo $year.$day;

能加到我代码上发给我下吗
public function pai3(&$actionno, &$actiontime, $time=null){ $this->settimeno($actiontime, $time); //echo $actiontime,' ',date('y-m-d h:i:s', $time); $year = date('y', $time); $day = str_pad(date('z',$time),3,'0',str_pad_left); $times = $year.$day; if($actiontime >= date('y-m-d h:i:s', $time)){ $actionno = $times-6; }else{ $actionno = $times-6; $actiontime=date('y-m-d 18:30', $time); } }