php 如何轮循
我是想求能满足多少个订单？为什么我这样不行？？
$order_id = mysql_query(select order_id from myr_order where '.strtotime('-'.$date.' day').' while($t_id = mysql_fetch_array($order_id,mysql_assoc)){
$is_in =1;
$num = 0;
$que = mysql_query(select goods_sn,order_id from myr_order_goods where order_id = '.$t_id['order_id'].');
while($gs = mysql_fetch_object($que)){
if(in_array($gs->goods_sn,$sn) && $is_in==1){
$is_in = 1;
}elseif(in_array($gs->goods_sn,$sn) && $is_in==0){
$is_in = 0;
break;
}
}
if($is_in == 1){
$num = $num + 1;
}elseif($is_in == 0){
continue;
}
}
  echo $num;
------解决方案--------------------
php code$sql = select order_id from myr_order where '.strtotime('-'.$date.' day').' goods_sn,$sn) && $is_in){ $is_in = 1; }elseif(in_array($gs->goods_sn,$sn) && !$is_in){ $is_in = 0; break; } if($is_in){ $num = $num + 1; }elseif(!$is_i){ continue; }} echo $num;