刚开始，根据我的想法，这个很简单嘛，上sql语句
delete from zqzrdp where tel in (select min(dpxx_id) from zqzrdp group by tel having count(tel)>1);
执行，报错！！~！~
异常意为：你不能指定目标表的更新在from子句。傻了，mysql 这样写，不行，让人郁闷。
难倒只能分步操作，蛋疼
以下是网友写的，同样是坑爹的代码，我机器上运行不了。
1. 查询需要删除的记录，会保留一条记录。
select a.id,a.subject,a.receiver from test1 a left join (select c.subject,c.receiver ,max(c.id) as bid from test1 c where status=0 group by receiver,subject having count(1) >1) b on a.id 1) and rowid not in (select min(rowid) from people group by peopleid having count(peopleid )>1)
5.删除表中多余的重复记录（多个字段），只留有rowid最小的记录
delete from vitae a where (a.peopleid,a.seq) in (select peopleid,seq from vitae group by peopleid,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleid,seq having count(*)>1)
看来想偷懒使用一句命令完成这个事好像不太显示，还是老老实实的分步处理吧，思路先建立复制一个临时表，然后对比临时表内的数据，删除主表里的数据
alter table tablename add autoid int auto_increment not null; create table tmp select min(autoid) as autoid from tablename group by name,address; create table tmp2 select tablename.* from tablename,tmp where tablename.autoid = tmp.autoid; drop table tablename; rename table tmp2 to tablename;