平行四边形是指具有两对平行边的四边形，其中对边长度相等，对角线度量相等。
in this article we are going to find all possible coordinates of a parallelogram.
basically, we will find all the possible coordinates from the given three coordinates to make a parallelogram of a non-zero area. here the three given coordinates are not fixed points and can change.
因此，如果给出三个坐标，我们可以断言只有这三个坐标可以构建一个平行四边形。
as per diagram given above, the opposite sides of a parallelogram are equal in length i.e., ad = bc and ab = cd, we can calculate the coordinates of the missing point (d) as
ad = bc
(dx - ax, dy - ay) = (cx - bx, cy - by)
dx = ax + cx - bx
dy = ay + cy - by
让我们开始吧！
展示给你一些实例instance-1假设这三个点是 −
{a1 = 3, a2 = 2}, {b1 = 1, b2 = 0}, {c1 = 4, c2 = 2}
after finding all possible coordinates of a parallelogram, result will be −
the (x, y) coordinates are −
0, 0
6, 4
2, 0
instance-2假设这三个点是 −
{a1 = 7, a2 = 2}, {b1 = 3, b2 = 0}, {c1 =0, c2 = 1}
after finding all possible coordinates of a parallelogram, result will be −
the (x,y) coordinates are −
10, 1
4, 3
-4, -1
algorithmstep 1 − declare the three coordinates of parallelogram.
step 2 − find the other possible coordinates using the formula.
step 3 − print the result.
multiple approaches我们以不同的方法提供了解决方案。
通过使用静态输入值
通过用户定义的方法
让我们逐个查看程序及其输出。
方法一：通过使用静态输入值在这种方法中，我们将把这三个点作为静态输入，并应用公式来打印结果。
examplepublic class main{ // main method public static void main(string[] args){ //declare the three coordinates of parallelogram int a1 = 3, a2 = 2; int b1 = 1, b2 = 0; int c1 = 4, c2 = 2; //find the other possible coordinates and printing it system.out.println(the (x,y) coordinates are: ); system.out.println(a1 + b1 - c1 + , + (a2 + b2 - c2)); system.out.println(a1 + c1 - b1 + , + (a2 + c2 - b2)); system.out.println(c1 + b1 - a1 + , + (c2 + b2 - a2)); }}
outputthe (x,y) coordinates are: 0, 06, 42, 0
approach-2: by using user defined methodin this approach, first we will initialise a user defined method and we will take the three points as input and apply the formula to print the result.
examplepublic class main { // main method public static void main(string[] s){ //declare the three coordinates of parallelogram int a1 = 7, a2 = 2; int b1 = 3, b2 = 0; int c1 = 0, c2 = 1; //calling user defined function func(a1, a2, b1, b2, c1, c2); } //user defined function static void func(int a1, int a2, int b1, int b2, int c1, int c2){ //find the other possible coordinates and printing it system.out.println(the (x,y) coordinates are: ); system.out.println(a1 + b1 - c1 + , + (a2 + b2 - c2)); system.out.println(a1 + c1 - b1 + , + (a2 + c2 - b2)); system.out.println(c1 + b1 - a1 + , + (c2 + b2 - a2)); }}
outputthe (x,y) coordinates are: 10, 14, 3-4, -1
在这篇文章中，我们探讨了如何通过使用不同的方法在java中找到平行四边形的所有可能坐标。
以上就是在java中找到平行四边形的所有可能坐标的详细内容。