这篇文章主要介绍了php日期函数date格式化unix时间的方法,实例分析了php中date函数的使用技巧,需要的朋友可以参考下
本文实例讲述了php日期函数date格式化unix时间的方法。分享给大家供大家参考。具体分析如下：
日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出
使用到函数语法如下
string date (string $format);string date (string $format, int $time);
下面是演示代码
<?phpecho "when this page was loaded,\n";echo 'it was then ', date ('r'), "\n";echo 'the currend date was ', date ('f j, y'), "\n";echo 'the currend date was ', date ('m j, y'), "\n";echo 'the currend date was ', date ('m/d/y'), "\n";echo 'the currend date was the ', date ('js \o\f m, y'), "\n";echo 'the currend time was ', date ('g:i:s a t'), "\n";echo 'the currend time was ', date ('h:i:s o'), "\n";echo date ('y');date ('l')?(print ' is'):(print ' is not');echo " a leap year\n";echo time ('u'), " seconds had elapsed since january 1, 1970.\n";?>
输出结果如下
it was then sat, 26 dec 2009 07:09:51 +0000the currend date was december 26, 2009the currend date was dec 26, 2009the currend date was 12/26/09the currend date was the 26th of dec, 2009the currend time was 7:09:51 am gmtthe currend time was 07:09:51 +00002009 is not a leap year1261811391 seconds had elapsed since january 1, 1970.